document.write( "Question 616686: Sketch the hyperbolas. Identify the center, asymptotes, vertices, and foci.
\n" ); document.write( "(x-3)^2/9 - (y+5)^2/16 = 1
\n" ); document.write( "

Algebra.Com's Answer #387846 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Sketch the hyperbolas. Identify the center, asymptotes, vertices, and foci.
\n" ); document.write( "(x-3)^2/9 - (y+5)^2/16 = 1
\n" ); document.write( "**
\n" ); document.write( "Equation is that of a hyperbola with vertical transverse axis.
\n" ); document.write( "Its standard form: (y-k)^2/a^2-(x-h)^2/b^2=1, (h,k)=(x,y) coordinates of the center
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (0,0)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "vertices: (0, 0±a)=(0,0±4)=(0,-4) and (0,4)
\n" ); document.write( "..
\n" ); document.write( "b^2=9
\n" ); document.write( "b=√9=3
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2=16+9=25
\n" ); document.write( "c=√25=5
\n" ); document.write( "foci:(0, 0±c)=(0,0±5)=(0,-5) and (0,5)
\n" ); document.write( "...
\n" ); document.write( "slopes of asymptotes with vertical transverse axis=±a/b=±4/3
\n" ); document.write( "asymptotes are straight lines which intersect at the center.
\n" ); document.write( "equation:y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "y-intercept=0, since asymptotes go thru the origin(0,0)
\n" ); document.write( "equation of asymptote with negative slope: y=-4x/3
\n" ); document.write( "equation of asymptote with positive slope: y=4x/3
\n" ); document.write( "..
\n" ); document.write( "see graph below:
\n" ); document.write( "y=±(16+16x^2/9)^.5\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );