document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616702>Question 616702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a line that is perpendicular to the line y=1/9x+3 ad contains the point (-3,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387845 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a line that is perpendicular to the line y=1/9x+3 ad contains the point (-3,0)<BR>\n" );
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document.write( "equation for a straight line:y=mx+b, m=slope, b=y-intercept<BR>\n" );
document.write( "slope of given line=1/9<BR>\n" );
document.write( "slope of line perpendicular to given line=-9 (negative reciprocal)<BR>\n" );
document.write( "equation: y=-9x+b<BR>\n" );
document.write( "solve for b using coordinates of given point (-3,0)<BR>\n" );
document.write( "0=-9*-3+b<BR>\n" );
document.write( "b=-27<BR>\n" );
document.write( "equation: y=-9x-27 </SPAN>\n" );
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