document.write( "Question 616643: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then it height h after t seconds is given by the equation h=-16t squared +vt+s, where h is in feet. if the object is propelled from a height of 4 feet with an initial velocity of 64 feet per second, its height h is given by the equation h =-16t squared+ 64t+4.\r
\n" ); document.write( "\n" ); document.write( "After how many seconds is the height 32 feet? \n" ); document.write( "
Algebra.Com's Answer #387831 by lwsshak3(11628)\"\" \"About 
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If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then it height h after t seconds is given by the equation h=-16t squared +vt+s, where h is in feet. if the object is propelled from a height of 4 feet with an initial velocity of 64 feet per second, its height h is given by the equation h =-16t squared+ 64t+4.
\n" ); document.write( "After how many seconds is the height 32 feet?
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\n" ); document.write( "h =-16t squared+ 64t+4
\n" ); document.write( "32=-16t^2+64t+4
\n" ); document.write( "set equation=0
\n" ); document.write( "0=-16t^2+64t+4-32
\n" ); document.write( "0=-16t^2+64t-28
\n" ); document.write( "divide by 4
\n" ); document.write( "0=-4t^2+16t-7
\n" ); document.write( "4t^2-16t+7=0
\n" ); document.write( "(2t-7)(2t-1)=0
\n" ); document.write( "t=1/2 sec (object on the way up)
\n" ); document.write( "or
\n" ); document.write( "t=7/2 sec (object on the way down)
\n" ); document.write( "ans:
\n" ); document.write( "object is at a height of 32 ft after 1/2 sec and 7/2 sec
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