document.write( "Question 616507: If 12 men and 16 boys can do a piece of work in 5 days and 13 men and 24 boys can do the same piece of work in 4 days. How long will 7 men and 10 boys take to complete the same work?\r
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Algebra.Com's Answer #387821 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! f 12 men and 16 boys can do a piece of work in 5 days and \n" ); document.write( "13men and 24 boys can do the same piece of work in 4 days. \n" ); document.write( " how long will 7 men and 10 boys take to complete the same work? \n" ); document.write( ": \n" ); document.write( "Let b = days required for one boy to do the job \n" ); document.write( "Let m = days required for one man to do the job \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "\"If 12 men and 16 boys can do a piece of work in 5 days\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"13men and 24 boys can do the same piece of work in 4 days.\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "We can combine the two equations \n" ); document.write( " \n" ); document.write( "combine like terms \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "8b = 16m \n" ); document.write( "divide by 8 \n" ); document.write( "b = 2m \n" ); document.write( ": \n" ); document.write( "Use the 1st scenario equation to find m, replace b with 2m \n" ); document.write( " \n" ); document.write( "reduce the fraction \n" ); document.write( " \n" ); document.write( "Multiply by m \n" ); document.write( "60+40 = m \n" ); document.write( "m = 100 days for one man to do the job \n" ); document.write( "then \n" ); document.write( "b = 2(100) \n" ); document.write( "b = 200 days for one boy to do the job \n" ); document.write( ": \n" ); document.write( "\" how long will 7men and 10 boys take to complete the same work? \n" ); document.write( "let t = time required for this to happen \n" ); document.write( " \n" ); document.write( "reduce the fraction, to give us a common denominator \n" ); document.write( " \n" ); document.write( "mult by 100 \n" ); document.write( "7t + 5t = 100 \n" ); document.write( "12t = 100 \n" ); document.write( "t = 100/12 \n" ); document.write( "t = 8 \n" ); document.write( " \n" ); document.write( " |