document.write( "Question 616507: If 12 men and 16 boys can do a piece of work in 5 days and 13 men and 24 boys can do the same piece of work in 4 days. How long will 7 men and 10 boys take to complete the same work?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #387821 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
f 12 men and 16 boys can do a piece of work in 5 days and
\n" ); document.write( "13men and 24 boys can do the same piece of work in 4 days.
\n" ); document.write( " how long will 7 men and 10 boys take to complete the same work?
\n" ); document.write( ":
\n" ); document.write( "Let b = days required for one boy to do the job
\n" ); document.write( "Let m = days required for one man to do the job
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "\"If 12 men and 16 boys can do a piece of work in 5 days\"
\n" ); document.write( "\"%2812%285%29%29%2Fm\" + \"%2816%285%29%29%2Fb\" = 1
\n" ); document.write( "\"60%2Fm\" + \"80%2Fb\" = 1
\n" ); document.write( ":
\n" ); document.write( "\"13men and 24 boys can do the same piece of work in 4 days.\"
\n" ); document.write( "\"%2813%284%29%29%2Fm\" + \"%2824%284%29%29%2Fb\" = 1
\n" ); document.write( "\"52%2Fm\" + \"96%2Fb\" = 1
\n" ); document.write( ":
\n" ); document.write( "We can combine the two equations
\n" ); document.write( "\"60%2Fm\" + \"80%2Fb\" = \"52%2Fm\" + \"96%2Fb\"
\n" ); document.write( "combine like terms
\n" ); document.write( "\"60%2Fm\" - \"52%2Fm\" = \"96%2Fb\" - \"80%2Fb\"
\n" ); document.write( "\"8%2Fm\" = \"16%2Fb\"
\n" ); document.write( "cross multiply
\n" ); document.write( "8b = 16m
\n" ); document.write( "divide by 8
\n" ); document.write( "b = 2m
\n" ); document.write( ":
\n" ); document.write( "Use the 1st scenario equation to find m, replace b with 2m
\n" ); document.write( "\"60%2Fm\" + \"80%2F%282m%29\" = 1
\n" ); document.write( "reduce the fraction
\n" ); document.write( "\"60%2Fm\" + \"40%2Fm\" = 1
\n" ); document.write( "Multiply by m
\n" ); document.write( "60+40 = m
\n" ); document.write( "m = 100 days for one man to do the job
\n" ); document.write( "then
\n" ); document.write( "b = 2(100)
\n" ); document.write( "b = 200 days for one boy to do the job
\n" ); document.write( ":
\n" ); document.write( "\" how long will 7men and 10 boys take to complete the same work?
\n" ); document.write( "let t = time required for this to happen
\n" ); document.write( "\"%287t%29%2F100\" + \"%2810t%29%2F200\" = 1
\n" ); document.write( "reduce the fraction, to give us a common denominator
\n" ); document.write( "\"%287t%29%2F100\" + \"5t%2F100\" = 1
\n" ); document.write( "mult by 100
\n" ); document.write( "7t + 5t = 100
\n" ); document.write( "12t = 100
\n" ); document.write( "t = 100/12
\n" ); document.write( "t = 8\"1%2F3\" days for 7 men and 10 boys to do the job
\n" ); document.write( "
\n" ); document.write( "
\n" );