document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57084>Question 57084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE LENGTH OF A RECTANGULAR GARDEN IS 8FT LESS THAN 3 TIMES IT'S WIDTH. IF THE PERIMETER OF THE GARDEN IS 48FT, FIND THE DIMENSIONS OF THE GARDEN.\r<BR>\n" );
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document.write( "IF SOMEONE CAN PLEASE HELP I WOULD APPRECIATE IT </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38782 by </B><A HREF=/tutors/aboutme.mpl?userid=Scriptor><B>Scriptor(36)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Scriptor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the length = x<BR>\n" );
document.write( "Call the width = y <BR>\n" );
document.write( "You know that x*y = 48<BR>\n" );
document.write( "You also know that x = 3y - 8 <BR>\n" );
document.write( "Substitute this x in x*y=48 to obtain: <BR>\n" );
document.write( "y * (3y-8) = 48 <BR>\n" );
document.write( "3y² - 8y - 48 = 0<BR>\n" );
document.write( "Now solve this for y (delete the negative root)<BR>\n" );
document.write( "Solution: y = 4/3 + 4*sqrt(10)/3 \r<BR>\n" );
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document.write( "          x = 48 / (4/3 + 4*sqrt(10)/3) </SPAN>\n" );
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