document.write( "Question 616627: help Solve the inequality.\r
\n" ); document.write( "\n" ); document.write( "x-5 < 1
\n" ); document.write( "___
\n" ); document.write( "x+4 \n" ); document.write( "

Algebra.Com's Answer #387811 by Edwin McCravy(20059) $\"\"$ $\"About$

You can put this solution on YOUR website!
help Solve the inequality.
\n" ); document.write( "

\r\n" );
document.write( " < 1 \r\n" );
document.write( "\r\n" );
document.write( "Subtract 1 from both sides:\r\n" );
document.write( "\r\n" );
document.write( " - 1 < 0\r\n" );
document.write( "\r\n" );
document.write( " -  < 0\r\n" );
document.write( "\r\n" );
document.write( "Get an LCD of (x+4) and multiply the  by  < 0\r\n" );
document.write( "\r\n" );
document.write( " - · < 0\r\n" );
document.write( "\r\n" );
document.write( " -  < 0\r\n" );
document.write( "\r\n" );
document.write( "Combine the numerators over the LCD:\r\n" );
document.write( "\r\n" );
document.write( " < 0\r\n" );
document.write( "\r\n" );
document.write( " < 0\r\n" );
document.write( "\r\n" );
document.write( " < 0\r\n" );
document.write( "\r\n" );
document.write( "To find the critical number, set x+4 = 0, getting x = -4\r\n" );
document.write( "\r\n" );
document.write( "Since there is only one critical number we have only two\r\n" );
document.write( "intervals to test:\r\n" );
document.write( "\r\n" );
document.write( "Interval          | (-oo,-4)  |  (-4, oo) |\r\n" );
document.write( "Test value        |    -5     |      0    |\r\n" );
document.write( "Sign of left side |           |           |\r\n" );
document.write( "\r\n" );
document.write( "The left side is  \r\n" );
document.write( "\r\n" );
document.write( "We substitute test value -5 in \r\n" );
document.write( " = 9 which is positive so we put a +\r\n" );
document.write( "\r\n" );
document.write( "Interval          | (-∞,-4)  |  (-4, ∞) |\r\n" );
document.write( "Test value        |    -5    |      0   |\r\n" );
document.write( "Sign of left side |     +    |          |\r\n" );
document.write( "\r\n" );
document.write( "We substitute test value 0 in \r\n" );
document.write( " =  which is negative so we put a -\r\n" );
document.write( "\r\n" );
document.write( "Interval          | (-∞,-4)  |  (-4, ∞) |\r\n" );
document.write( "Test value        |    -5    |      0   |\r\n" );
document.write( "Sign of left side |     +    |      -   |\r\n" );
document.write( "\r\n" );
document.write( "Since it's < 0 we choose the interval (-4, ∞) as the solution\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );