document.write( "Question 616485: I am trying to find the solutions to:
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document.write( "(x^2-3)^2-43(x^2-3)+42=0
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document.write( "I can not figure out how to turn it into a quadratic and solve it. \n" );
document.write( "
Algebra.Com's Answer #387706 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! (x^2-3)^2-43(x^2-3)+42=0 \n" ); document.write( "let u=(x^2-3) \n" ); document.write( "u^2-43u+42=0 \n" ); document.write( "(u-42)(u-1)=0 \n" ); document.write( "u=1=x^2-3 \n" ); document.write( "x^2=4 \n" ); document.write( "x=±√4=±2 \n" ); document.write( "or \n" ); document.write( "x=42=x^2-3 \n" ); document.write( "x^2=45 \n" ); document.write( "x=±√45 \n" ); document.write( "solution: x=-√45, -2, 2, √45 \n" ); document.write( " |