document.write( "Question 616490: (x^2-1)^2-14(x^2-1)+33=0
\n" ); document.write( "I need to find the solutions for this, but can not figure out how to solve it. Any help so I can learn this would be very much appreciated. \n" ); document.write( "
Algebra.Com's Answer #387697 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Notice that if I:
\n" ); document.write( "Let y = (x^2-1)
\n" ); document.write( "then I can rewrite:
\n" ); document.write( "(x^2-1)^2-14(x^2-1)+33=0
\n" ); document.write( "as:
\n" ); document.write( "y^2-14y+33=0
\n" ); document.write( "Now, it looks like a regular quadratic which we can factor as:
\n" ); document.write( "(y-3)(y-11) = 0
\n" ); document.write( "y = {3, 11}
\n" ); document.write( ".
\n" ); document.write( "But we don't what 'y' we want to know what 'x' is.
\n" ); document.write( "so set both to:
\n" ); document.write( "y = (x^2-1)
\n" ); document.write( "and solve for x:
\n" ); document.write( ".
\n" ); document.write( "3 = x^2-1
\n" ); document.write( "4 = x^2
\n" ); document.write( "+- 2 = x
\n" ); document.write( ".
\n" ); document.write( "11 = x^2-1
\n" ); document.write( "12 = x^2
\n" ); document.write( "sqrt(12) = x
\n" ); document.write( "2*sqrt(3) = x
\n" ); document.write( ".
\n" ); document.write( "x = {-2*sqrt(3), 2*sqrt(3), -2, 2}
\n" ); document.write( " \n" ); document.write( "
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