document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616398>Question 616398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have two saltwater solutions. One consists of 20% salt, and the other consists of 15% salt. \r<BR>\n" );
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document.write( "A. If you want to add these two together to make 5 gallons of a 17% solution, how much of each solution should you add?\r<BR>\n" );
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document.write( "B. If you wanted to make 5 gallons of a 19% solution, what volume of each solution should you add? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387662 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do them like this:<BR>\n" );
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document.write( "if a 14% acid solution is mixed with a 19% acid solution to produce 45 gallons of a 15% acid solution how much (in gallons) of each solution should be used?<BR>\n" );
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document.write( "f = 14%<BR>\n" );
document.write( "n = 19%<BR>\n" );
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document.write( "f + n = 45 (total gallons)<BR>\n" );
document.write( "14f + 19n = 15*45 (total acid)<BR>\n" );
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document.write( "n = 45 - f<BR>\n" );
document.write( "Sub for n<BR>\n" );
document.write( "14f + 19*(45-f) = 675<BR>\n" );
document.write( "14f + 855 - 19f = 675<BR>\n" );
document.write( "-5f = -180<BR>\n" );
document.write( "f = 36 gallons of 14%<BR>\n" );
document.write( "n = 9 gallons of 19% </SPAN>\n" );
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