document.write( "Question 57054This question is from textbook MCDOUGAL LITTELL ALGEBRA 1
\n" ); document.write( ": Rewrite the equation so that y is a function of x\r
\n" ); document.write( "\n" ); document.write( "Please explain and show work on each step so that I will fully understand this for the future problems that I have. THANK YOU!\r
\n" ); document.write( "\n" ); document.write( "3(x-2y) = -12(x+2y)
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Algebra.Com's Answer #38763 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"3%28x+-+2y%29+=+-12%28x+%2B+2y%29\"
\n" ); document.write( "use the distributive law to factor the equation
\n" ); document.write( "\"3x+-+6y+=+-12x+-+24y\"
\n" ); document.write( "add 24y to both sides
\n" ); document.write( "\"3x+-+6y+%2B+24y+=+-12x+-+24y+%2B+24y\"
\n" ); document.write( "\"3x+-+6y+%2B+24y+=+-12x\"
\n" ); document.write( "subtract 3x from both sides
\n" ); document.write( "\"3x+-+3x+-6y++%2B+24y+=+-12x+-+3x\"
\n" ); document.write( "\"-6y+%2B+24y+=+-+12x+-+3x\"
\n" ); document.write( "\"18y+=+-15x\"
\n" ); document.write( "divide both sides by 18
\n" ); document.write( "\"y+=+%28-15%2F18%29%2Ax\"
\n" ); document.write( "simplify -15/18 to -5/6
\n" ); document.write( "\"y+=+%28-5%2F6%29%2Ax\" answer
\n" ); document.write( "you can check this answer by plugging it back into the original equation
\n" ); document.write( "\"3%28x+-+2%28%28-5%2F6%29%2Ax%29%29+=+-12%28x+%2B+2%28%28-5%2F6%29%2Ax%29%29\"
\n" ); document.write( "\"3%28x+%2B+%2810%2F6%29%2Ax%29+=+-12%28x+-+%2810%2F6%29%2Ax%29\"
\n" ); document.write( "simplify 10/6 to 5/3
\n" ); document.write( "\"3%28x+%2B+%285%2F3%29%2Ax%29+=+-12%28x+-+%285%2F3%29%2Ax%29\"
\n" ); document.write( "note that x = (3/3)*x
\n" ); document.write( "\"3%28%283%2F3%29%2Ax+%2B+%285%2F3%29%2Ax%29+=+-12%28%283%2F3%29%2Ax+-+%285%2F3%29%2Ax%29\"
\n" ); document.write( "\"3%28%288%2F3%29%2Ax%29+=+-12%28%28-2%2F3%29%2Ax%29\"
\n" ); document.write( "\"8x+=+%2824%2F3%29%2Ax\"
\n" ); document.write( "\"8x+=+8x\"
\n" ); document.write( "OK
\n" ); document.write( "checking answers is always a good idea when you have the time
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