document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56970>Question 56970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sam earned 1155 in interest on a total investment 15000 this past year, if part of the money was invested at 6% and the remainder at 9% how much was invested at 6% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38758 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let $x = the amount invested at 6%, then the remainder of ($15000 - $x) = the amount invested at 9%.  Changing the percents to their decimal equivalents (6% = 0.06 and 9% = 0.09), you can write the equation for this situation:\r<BR>\n" );
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document.write( "0.06x + 0.09(15000-x) = 1155 Simplify and solve for x.<BR>\n" );
document.write( "0.06x + 1350 - 0.09x = 1155<BR>\n" );
document.write( "-0.03x + 1350 = 1155 Subtract 1350 from both sides of the equation.<BR>\n" );
document.write( "-0.03x = -195  Divide both sides by -0.03<BR>\n" );
document.write( "x = $6500\r<BR>\n" );
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document.write( "The amount invested at 6% was $6500<BR>\n" );
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