document.write( "Question 616096: How do you solve 3r²-6r=-3 using the quadratic formula? \n" ); document.write( "

Algebra.Com's Answer #387562 by fcabanski(1391) $\"\"$ $\"About$

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$\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$

\n" ); document.write( "a is the coefficient of the squared element, b is the coefficient of the variable (x or in this case r), and c is the constant.

\n" ); document.write( " $\"3r%5E2+-+6r+=+-3\"$ | First move the constant to the left by adding 3 to both sides.

\n" ); document.write( " $\"3r%5E2+-+6r+%2B+3+=+0\"$ | Factor out any common factor. In this case it's 3.

\n" ); document.write( "{{3{r^2 - 2r + 1 = 0}}} | The removed factor drops because 3 = 0 is never true.

\n" ); document.write( " $\"r%5E2+-+2r+%2B+1\"$ | Now apply the quadratic formula.

\n" ); document.write( " $\"%282+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29+\"$ = $\"%282+%2B-+sqrt%28+4-4+%29%29%2F2+\"$ =

\n" ); document.write( " $\"2%2F2+=+1\"$

\n" ); document.write( "Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)
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