document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57032>Question 57032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello, i need help solving this equation and simplying my answer as much as possible, thanks so much!<BR>\n" );
document.write( "2x              3         1<BR>\n" );
document.write( "-------   -  ------  +  ------<BR>\n" );
document.write( "x^2+x-6       x+3        x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38755 by </B><A HREF=/tutors/aboutme.mpl?userid=BGluvsmath><B>BGluvsmath(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BGluvsmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x/(x^2+x-6) - 3/(x+3) + 1/(x-2)<BR>\n" );
document.write( "To get a common denominator (necessary for adding and subtracting fractions), multiply the 2nd term by x-2 and the 3rd term by x+3:<BR>\n" );
document.write( "2x/(x^2+x-6) - 3(x-2)/((x+3)(x-2)) + 1(x+3)/((x-2)(x+3))<BR>\n" );
document.write( "(x+3)(x-2) simplifies to x^2+x-6, so:<BR>\n" );
document.write( "2x-3(x-2)+(x+3)/(x^2+x-6)<BR>\n" );
document.write( "2x-3x+6+x+3/x^2+x-6<BR>\n" );
document.write( "The x's cancel out of the numerator, so this simplifies to:<BR>\n" );
document.write( "9/(x^2+x-6) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );