document.write( "Question 616136: A sample of 83 golfers showed that their average score on a particular golf course was 84.81 with a standard deviation of 5.99.
\n" ); document.write( "Answer each of the following (state the final answer to at least two decimal places.):
\n" ); document.write( "(A) Find the 90% confidence interval of the mean score for all 83 golfers.
\n" ); document.write( "(B) Find the 90% confidence interval of the mean score for all golfers if this is a sample of 130 golfers instead of a sample of 83.
\n" ); document.write( "(C) Which confidence interval is larger and why? \n" ); document.write( "

Algebra.Com's Answer #387538 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "A sample of 83 golfers showed that their average score on a particular golf course was 
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document.write( "84.81 with a standard deviation of 5.99. 
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document.write( " ME = 1.645[5.99/sqrt(83)] = 1.0816
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document.write( "CI: 84.81-1.0816< u < 84.81+1.0816		
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document.write( "CI: 83.7284 < u < 85.8916		\r
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document.write( " ME = 1.645[5.99/sqrt(130)] = .8642
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document.write( "CI: 84.81-.8642 < u < 84.81+.8642		
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document.write( "CI: 83.9458 < u < 85.6742		
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document.write( "(C) Which confidence interval is larger and why?
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document.write( "Smaller sample has the larger confidence Interval. 
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document.write( "the larger the sample the smaller the confidence interval is. \n" );
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