document.write( "Question 616104: find the annual intrest rate if an investment of $4000 earns $75 in intrest over 3 years \n" ); document.write( "
Algebra.Com's Answer #387506 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi, 
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document.write( "In General \"A+=+P%281%2Br%2Fn%29%5Ent\"
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document.write( "A = Accumulated Amount $4075
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document.write( "P= principal = $4000
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document.write( "r= annual rate = r
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document.write( "n= periods per year = 1 
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document.write( "t= years = 3 
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document.write( "\"A%2F+P+=+1.01875+=++%281%2Br%29%5E3\"
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document.write( "    log(1.01875) = 3log(1+r)
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document.write( "    log(1.01875)/3 = .0027 =  log(1+r)
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document.write( "             \"10%5E%28.0027%29+=+1%2Br\"
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document.write( "                     .0062 = r  OR  Interest rate is .62% \n" );
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