document.write( "Question 7044: find all the roots of each equation.
\n" ); document.write( "x^4+4x^3+6x^2+8x+8=0
\n" ); document.write( "

Algebra.Com's Answer #3875 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
you need to factorise this: \"x%5E4%2B4x%5E3%2B6x%5E2%2B8x%2B8=0\". Seeing as how they have asked you, and you know next to nothing about solving \"x%5E4\" polynomials, there has to be a \"nice\" solution for you. So, lets just re-order the polynomial slightly to:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E4%2B6x%5E2%2B8+%2B4x%5E3%2B8x=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Lets treat the first 3 terms as a quadratic and the last 2 terms we will just factorise normally: So\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2%29%28x%5E2%2B4%29+%2B+4x%28x%5E2%2B2%29+=+0\". Both of these terms have a common term, namely \"%28x%5E2%2B2%29\", so we can factorise again to give:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2%29%28x%5E2+%2B+4+%2B+4x%29+=+0\" and the second bracket can be factorised to give\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2%29%28x%2B2%29%28x%2B2%29+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so either \"x%5E2%2B2+=+0\" or x+2 = 0
\n" ); document.write( "so either \"x%5E2+=+-2\" or x = -2
\n" ); document.write( "so either \"x+=+%2B+sqrt%28-2%29\" or \"x+=+-+sqrt%28-2%29\" or x = -2\r
\n" ); document.write( "\n" ); document.write( "--> \"x+=+%2B+sqrt%282%29i\" or \"x+=+-+sqrt%282%29i\" or x = -2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "jon.
\n" ); document.write( "
\n" ); document.write( "
\n" );