document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616131>Question 616131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> scott is 4 times olderthan bethany. In 6 years scott will only be 3 times older than bethany, what are 2 equations? and how old are they?  please help I am totally stuck...thanks heaps </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387499 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  scott is 4 times olderthan bethany. In 6 years scott will only be 3 times older than bethany, what are 2 equations?<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "s = 4b<BR>\n" );
document.write( "(s+6) = 3(b+6)<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "Substitute for \"s\" and solve for \"b\":<BR>\n" );
document.write( "4b + 6 = 3b + 18<BR>\n" );
document.write( "b = 12 (Bethany's age now)<BR>\n" );
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document.write( "Solve for \"s\":<BR>\n" );
document.write( "s = 4b<BR>\n" );
document.write( "s = 4*12 = 48 (Scott's age now)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
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