document.write( "Question 616075: Movie tickets are $4 for regular admission and $3 for seniors. On a night where there were 190 people and total sales of $720, how many regular admission tickets were sold? \n" ); document.write( "
Algebra.Com's Answer #387473 by dragonwalker(73)![]() ![]() ![]() You can put this solution on YOUR website! Let us say that the total number of regular admission tickets is a and the total number of senior tickets is s.\r \n" ); document.write( "\n" ); document.write( "So each sale of one of these tickets brings in $4 and $3 respectively\r \n" ); document.write( "\n" ); document.write( "So:\r \n" ); document.write( "\n" ); document.write( "(a x 4) + (s x 3) is the total sales which is $720\r \n" ); document.write( "\n" ); document.write( "i.e. \r \n" ); document.write( "\n" ); document.write( "4a + 3s = 720\r \n" ); document.write( "\n" ); document.write( "We also know the total number of people was 190 so:\r \n" ); document.write( "\n" ); document.write( "a + s = 190\r \n" ); document.write( "\n" ); document.write( "So if we rearrange the second equation we can get:\r \n" ); document.write( "\n" ); document.write( "s = 190 - a\r \n" ); document.write( "\n" ); document.write( "Now we substitute this into the first equation:\r \n" ); document.write( "\n" ); document.write( "4a + 3(190 - a) = 720\r \n" ); document.write( "\n" ); document.write( "4a + (570 - 3a) = 720\r \n" ); document.write( "\n" ); document.write( "4a + 570 - 3a = 720\r \n" ); document.write( "\n" ); document.write( "4a - 3a = 720 - 570\r \n" ); document.write( "\n" ); document.write( "a = 150\r \n" ); document.write( "\n" ); document.write( "so 150 regular admission tickets were sold !!! \n" ); document.write( " |