document.write( "Question 56989: I need your help onthe following problem: \"A rectangle whose perimeter is 250 is 8 feet shorter than it is wide.Find the dimensions and area.\" Can you please help me. \n" ); document.write( "
Algebra.Com's Answer #38743 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangle whose perimeter is 250 is 8 feet shorter than it is wide.Find the dimensions and area.\" Can you please help me.
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\n" ); document.write( "It says: 2L + 2W = 250
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\n" ); document.write( "It also says: L = W - 8
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\n" ); document.write( "Sustitute (W-8) for L in the perimeter equation:
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\n" ); document.write( "2(W-8) + 2W = 250
\n" ); document.write( "2W - 16 + 2W = 250
\n" ); document.write( "4W = 250 + 16
\n" ); document.write( "4W = 266
\n" ); document.write( "W = 266/4
\n" ); document.write( "W = 66.5 ft is the width
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\n" ); document.write( "L = 66.5 - 8 = 58.5 ft is the length
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\n" ); document.write( "Check our solutions in the perimeter equation:
\n" ); document.write( "2(58.5) + 2(66.5) =
\n" ); document.write( " 117 + 133 = 250
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\n" ); document.write( "Find the area: 58.5 * 66.5 = 3890.25 sq ft
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\n" ); document.write( "Make sense to you??\r
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