document.write( "Question 615969: I am 62 and am tutoring a 50-year old woman who needs to pass the entrance exam for a college algebra class at the University of Maine in Augusta this Fall. I have done this question by calulator for an answer of B=1.08, but she reduced the fractions longhand and got B=0.1. Doing it her way step-by-step I see the problem is in the cross-products, but I cannot write it out in a step-by-step fashion to get the right answer either. Would you please write out the step-by-step reduction for me? The question is:\r
\n" ); document.write( "\n" ); document.write( "3¼/2 = B/two-thirds, that is 3 and one-quarter over 2 = B over two-thirds.\r
\n" ); document.write( "\n" ); document.write( "Thank you. I see my student again next Tuesday, June 5th, Bob Gross \n" ); document.write( "
Algebra.Com's Answer #387419 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your equation is:
\n" ); document.write( "(3+1/4) / 2 = B / (2/3)
\n" ); document.write( "you can make an improper fraction out of 3+1/4.
\n" ); document.write( "it becomes (13/4)
\n" ); document.write( "your equation becomes:
\n" ); document.write( "(13/4) / 2 = B / (2/3)
\n" ); document.write( "cross multiply to get:
\n" ); document.write( "(13/4) * (2/3) = 2 * B
\n" ); document.write( "this is equivalent to:
\n" ); document.write( "(13*2) / (4*3) = 2 * B
\n" ); document.write( "simplify this further to get:
\n" ); document.write( "26 / 12 = 2 * B
\n" ); document.write( "divide both sides of this equation by 2 to get:
\n" ); document.write( "13 / 12 = B
\n" ); document.write( "decimal equivalent of 13 / 12 = 1.08333333333 which rounds to 1.08 or 1.083 or whatever detail you want to go out to.
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