document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=615935>Question 615935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me\r<BR>\n" );
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document.write( "it says to solve by using elimination method\r<BR>\n" );
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document.write( "x + 8y = 14 \r<BR>\n" );
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document.write( "-3x + 4y = 0\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387389 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying 1st equation by 3 ___ 3x + 24y = 42\r<BR>\n" );
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document.write( "adding 2nd equation (to eliminate x) ___ 28y = 42\r<BR>\n" );
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document.write( "solve for y, then substitute back to find x </SPAN>\n" );
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