document.write( "Question 615761: Find all the solution of the equation in the interval (0,2pi) \r
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document.write( "sec^2x-1=0\r
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document.write( "sinx-2=cosx-2 \n" );
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Algebra.Com's Answer #387360 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Find all the solution of the equation in the interval (0,2pi) \n" ); document.write( "sec^2x-1=0 \n" ); document.write( "tan^2x=1 \n" ); document.write( "tan x=±√1=±1 \n" ); document.write( "x=π/4, 3π/4, 5π/4, and 7π/4 \n" ); document.write( ".. \n" ); document.write( "sinx-2=cosx-2 \n" ); document.write( "sinx=cosx \n" ); document.write( "sinx/cosx=1 \n" ); document.write( "tanx=1 \n" ); document.write( "x=π/4 and 5π/4 in quadrants I and III where tan>0 \n" ); document.write( " |