document.write( "Question 615874: angle A and angle B are supplementary. angle A is 20 more than 3 times angle B. how many degrees is angle B. please help \n" ); document.write( "
Algebra.Com's Answer #387350 by dragonwalker(73)![]() ![]() ![]() You can put this solution on YOUR website! So supplementary angles means they add up to 180 degrees\r \n" ); document.write( "\n" ); document.write( "as angle B is smaller then we should give it value x.\r \n" ); document.write( "\n" ); document.write( "So we have to find a formula that fits the size of Angle A.\r \n" ); document.write( "\n" ); document.write( "it is three time angle B + 20\r \n" ); document.write( "\n" ); document.write( "so: 3 times x +20\r \n" ); document.write( "\n" ); document.write( "3x+20\r \n" ); document.write( "\n" ); document.write( "So angle A is 3x+20 \n" ); document.write( "angle B is x\r \n" ); document.write( "\n" ); document.write( "Adding these together equals 180 so:\r \n" ); document.write( "\n" ); document.write( "3x+20 + x = 180\r \n" ); document.write( "\n" ); document.write( "solve for x:\r \n" ); document.write( "\n" ); document.write( "4x + 20 = 180 \n" ); document.write( "4x = 180-20 \n" ); document.write( "4x = 160 \n" ); document.write( "x = 160/4 \n" ); document.write( "x = 40\r \n" ); document.write( "\n" ); document.write( "So angle B is 40 degrees. \r \n" ); document.write( "\n" ); document.write( "To check. this would mean that angle A is 3 times 40 plus 20 = 120 + 20 \n" ); document.write( " = 140\r \n" ); document.write( "\n" ); document.write( "Add 140 + 40 = 180 !!! \n" ); document.write( " |