document.write( "Question 615867: my mum was 27 when i was born, 8 years ago she was twice as old as i shall be in 5 years time..how old am i now? \n" ); document.write( "
Algebra.Com's Answer #387348 by dragonwalker(73)\"\" \"About 
You can put this solution on YOUR website!
Okay, so we need to represent your age as an unknown. Let us say x.\r
\n" ); document.write( "\n" ); document.write( "Five years from now you are going to be x + 5\r
\n" ); document.write( "\n" ); document.write( "Eight years ago your mum was twice this i.e. 2(x+5) or 2x+10\r
\n" ); document.write( "\n" ); document.write( "It also gives a clue at how old your mum was 8 years ago in another way:
\n" ); document.write( "She was 27 + your age at the time and you would have been x-8. So this means she was:\r
\n" ); document.write( "\n" ); document.write( "27+x-8\r
\n" ); document.write( "\n" ); document.write( "As both formulas represent her age 8 years ago they are equal to each other so:\r
\n" ); document.write( "\n" ); document.write( "2x+10 = 27+x-8\r
\n" ); document.write( "\n" ); document.write( "Solve for x:\r
\n" ); document.write( "\n" ); document.write( "2x-x = 27-8-10
\n" ); document.write( "x=9\r
\n" ); document.write( "\n" ); document.write( "so you would be 9 years old.
\n" ); document.write( "
\n" ); document.write( "
\n" );