document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57018>Question 57018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the following system of equations<BR>\n" );
document.write( "3x-y=1<BR>\n" );
document.write( "y=-x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38731 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, solve both equations for y and you get y=3x-1 and y=-x+3.  Plot those out by creating some ordered pairs, draw the lines, and see where they interesect.  The point of intersection is the solution -- in this case, it's (1,2).  The graphs of the lines is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28200%2C200%2C-3%2C5%2C-3%2C5%2C3x-1%2C-x%2B3%29 ALIGN=MIDDLE  ALT=\"graph%28200%2C200%2C-3%2C5%2C-3%2C5%2C3x-1%2C-x%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );