document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=615725>Question 615725</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Starting with the data values 70 and 100, add three data values to the sample so that the mean is 96, the median is 97, and the mode is 97.  Please show all of your work.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387294 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the three values to be added be a,b & c \r<BR>\n" );
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document.write( "now given mean is 96\r<BR>\n" );
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document.write( " so, (70+a+b+c+100)/5 = 96 ----- eq.1\r<BR>\n" );
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document.write( "also given the median is 97, so if all the five numbers are ordered in either ascending order or descending order, the 3rd(median) value will be 97.\r<BR>\n" );
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document.write( "also given the mode is 97, so the value that is repeating or occurring the maximum no. of times is 97.\r<BR>\n" );
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document.write( "so, here out of the three values a,b,and c at least two should be 97.\r<BR>\n" );
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document.write( "from eq.1 70+a+97+97+100= 96*5\r<BR>\n" );
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document.write( "        =>364+a = 480<BR>\n" );
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document.write( "        => a = 116<BR>\n" );
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document.write( "so the data values are 70,97,97,100,116\r<BR>\n" );
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