document.write( "Question 615680: the sum of the digits of two digit number is 9.if the digits are reversed the new number is decresed by 9.find the number. \n" ); document.write( "
Algebra.Com's Answer #387277 by Maths68(1474)\"\" \"About 
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Let x be the tens digit
\n" ); document.write( "and y be the unit digit
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\n" ); document.write( "So,\r
\n" ); document.write( "\n" ); document.write( "10x + y = number
\n" ); document.write( "The sum of the digits of a number is 9.
\n" ); document.write( "x + y = 9............(1)\r
\n" ); document.write( "\n" ); document.write( "Reversing the digits decrease the number by 9.
\n" ); document.write( "10y + x = 10x + y - 9
\n" ); document.write( "10y - y = 10x - x - 9
\n" ); document.write( "9y = 9x - 9
\n" ); document.write( "9y = 9(x - 1)
\n" ); document.write( "Divide above equation by 9, we have
\n" ); document.write( "y = x - 1
\n" ); document.write( "y-x=-1..............(2)\r
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\n" ); document.write( "\n" ); document.write( "Add (1) and (2)\r
\n" ); document.write( "\n" ); document.write( "y - x = -1
\n" ); document.write( "x + y = 9
\n" ); document.write( "--------------
\n" ); document.write( "2y=8.........(2)\r
\n" ); document.write( "\n" ); document.write( "Divide by 2 both sides
\n" ); document.write( "2y/2=8/2
\n" ); document.write( "y = 4
\n" ); document.write( "Put the value of x in (1)
\n" ); document.write( "x+y=9
\n" ); document.write( "x+4=9
\n" ); document.write( "x=9-4
\n" ); document.write( "x=5\r
\n" ); document.write( "\n" ); document.write( "Digits are 5 and 4
\n" ); document.write( "and number is 54\r
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\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "The sum of the digits of a number is 9
\n" ); document.write( "5+4=9
\n" ); document.write( "9=9\r
\n" ); document.write( "\n" ); document.write( "Reversing the digits decrease the number by 9.
\n" ); document.write( "45=54-9
\n" ); document.write( "45=45\r
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