document.write( "Question 614722: Give the slope and the Y-intercept of the line and graph it.
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Algebra.Com's Answer #387154 by asuar010(338)\"\" \"About 
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"-8+x+%2B+3+y+=+0\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+--8%2F3\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/-8 = 0.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/3 = 0.
  • Slope is --8/3 = 2.66666666666667.
  • Equation in slope-intercept form: y=2.66666666666667*x+0.
\"graph%28+500%2C+500%2C+0-8%2C+0%2B8%2C+0-8%2C+0%2B8%2C+2.66666666666667%2Ax%2B0+%29+\"\n" ); document.write( "
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