document.write( "Question 615335: Jack, Kay, and Lynn deliver advertising flyers in a small town. If each person works alone, it takes Jack 4 hours to deliver all the flyers, and it takes Lynn 1 hour longer than it takes Kay. Working together, they can deliver all the flyers in 40% of the time it takes Kay working alone. How long does it take Kay to deliver all the flyers alone?
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Algebra.Com's Answer #387118 by lwsshak3(11628)\"\" \"About 
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Jack, Kay, and Lynn deliver advertising flyers in a small town. If each person works alone, it takes Jack 4 hours to deliver all the flyers, and it takes Lynn 1 hour longer than it takes Kay. Working together, they can deliver all the flyers in 40% of the time it takes Kay working alone. How long does it take Kay to deliver all the flyers alone?
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\n" ); document.write( "let x=hrs Kay takes to do the job alone
\n" ); document.write( "1/x= Kay's work rate
\n" ); document.write( "x+1=hrs Lynn takes to do the job alone
\n" ); document.write( "1/(x+1)=Lynn's work rate
\n" ); document.write( "4=hrs Jack takes to do the job alone(given)
\n" ); document.write( "1/4 =Jack's work rate
\n" ); document.write( ".4x=hrs to complete the job working together
\n" ); document.write( "..
\n" ); document.write( ".4x/x+.4x/(x+1)+.4x/4=100% of the job
\n" ); document.write( ".4+.4x/(x+1)+.x=1
\n" ); document.write( "multiply by 10
\n" ); document.write( "4+4x/(x+1)+x=10
\n" ); document.write( "LCD:(x+1)
\n" ); document.write( "4x+4+4x+x^2+x=10x+10
\n" ); document.write( "x^2-x-6=0
\n" ); document.write( "(x-3)(x+2)=0
\n" ); document.write( "x=-2 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=3
\n" ); document.write( "ans:
\n" ); document.write( "hrs Kay takes to do the job alone=3\r
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