document.write( "Question 615314: $1.95 in quarters and dimes was found in a couch. There were 4 times as many dimes as there were quarters. How many dimes and quarters were found in the couch\r
\n" ); document.write( "\n" ); document.write( "I can't make it past this point:
\n" ); document.write( "4(25x) + 10(y) = $1.95 \r
\n" ); document.write( "\n" ); document.write( "I let x represent quarters and y represent dimes
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Algebra.Com's Answer #387103 by Maths68(1474) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let
\n" ); document.write( "Quarters=x
\n" ); document.write( "Dimes=4x
\n" ); document.write( "$1.95=100*1.95 cents
\n" ); document.write( "$1.95=195 cents\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(Quarter)(x)+(Dime)(4x)=195
\n" ); document.write( "(25)(x)+10(4x)=195
\n" ); document.write( "25x+40x=195
\n" ); document.write( "65x=195
\n" ); document.write( "x=195/65
\n" ); document.write( "x=3\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Quarters=x=3
\n" ); document.write( "Dimes=4x=4(3)=12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "======
\n" ); document.write( "(3)(Quarter)+(12)(Dime)=195 cents
\n" ); document.write( "(3)(25)+(12)(10)=195
\n" ); document.write( "75+120=195
\n" ); document.write( "195=195\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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