document.write( "Question 615228: I have problems figuring out 3 questions\r
\n" );
document.write( "\n" );
document.write( "1) Assume that a procedure yields a binomial distribution with a trial repeated n=5 times. Find the probability of x= 2 successes given that the probability p=0.75 of successes on a single trial. \r
\n" );
document.write( "\n" );
document.write( "2) Assume that adults have IQ scores that are normally distributed with a mean of 102 and a standard deviation of 12. Find the IQ score that separates the bottom 25% from the top 75%\r
\n" );
document.write( "\n" );
document.write( "3) Heights of adult men are normally distributed with a mean of 69 inches and standard deviation of 2.8 inches. If an adult man is randomly selected, what is the probability that he is taller than 73.2 inches \n" );
document.write( "
Algebra.Com's Answer #387069 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1) Assume that a procedure yields a binomial distribution with a trial repeated n=5 times. Find the probability of x= 2 successes given that the probability p=0.75 of successes on a single trial. \n" ); document.write( "Ans: P(x = 2) = 5C2*0.75^2*0.25*3 = binompdf(5,0.75,2) = 0.0879 \n" ); document.write( "======================================================================= \n" ); document.write( "2) Assume that adults have IQ scores that are normally distributed with a mean of 102 and a standard deviation of 12. Find the IQ score that separates the bottom 25% from the top 75% \n" ); document.write( "Find the z-score with a left tail of 0.25 \n" ); document.write( "invNorm(0.25) = -0.6745 \n" ); document.write( "Find the corresponding \"IQ\" value using IQ = z*s + u \n" ); document.write( "IQ = -0.6745*12+102 = 93.9 \n" ); document.write( "==========================================\r \n" ); document.write( "\n" ); document.write( "3) Heights of adult men are normally distributed with a mean of 69 inches and standard deviation of 2.8 inches. If an adult man is randomly selected, what is the probability that he is taller than 73.2 inches \n" ); document.write( "z(73.2) = (73.2-69)/2 = 4.2/2 = 2.1 \n" ); document.write( "--- \n" ); document.write( "P(x > 73.2) = P(z > 2.1) = normalcdf(2.1,100) = 0.0179 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |