document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=615177>Question 615177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a square exceeds the area of a rectangle is 13squared. if the area of the square is y squared and the area of rectangle is (y+1)(y-3). find y.<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387064 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of a square exceeds the area of a rectangle is 13 squared. <BR>\n" );
document.write( "if the area of the square is y squared and the area of rectangle is (y+1)(y-3). find y.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Square area - rectangle area = 13^2<BR>\n" );
document.write( "y^2 - (y+1)(y-3) = 169<BR>\n" );
document.write( "FOIL<BR>\n" );
document.write( "y^2 - (y^2 - 2y - 3) = 169<BR>\n" );
document.write( "y^2 - y^2 + 2y + 3 = 169; removing the brackets changes the signs<BR>\n" );
document.write( "2y = 169 - 3<BR>\n" );
document.write( "2y = 166<BR>\n" );
document.write( "y = 166/2<BR>\n" );
document.write( "y = 83<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "See if that checks out<BR>\n" );
document.write( "83^2 - (84*80) = <BR>\n" );
document.write( "6889 - 6720 = 169 which is 13^2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );