document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=615309>Question 615309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the sin, cos and tan of 13pi/6 by using the unit circle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387062 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I find the sin, cos and tan of 13pi/6 by using the unit circle. <BR>\n" );
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document.write( "(13/6)pi = (2 1/6)pi = 2pi + (1/6)pi<BR>\n" );
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document.write( "2pi is one around the circle which gets you back to where you started.<BR>\n" );
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document.write( "sin (13pi/6) = sin(pi/6) = 1/2<BR>\n" );
document.write( "cos(13pi/6) = cos(pi/6) = sqrt(3)/2<BR>\n" );
document.write( "tan(13pi/6) = tan(pi/6) = (1/2)/(sqrt(3)/2) = 1/sqrt(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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