document.write( "Question 56960: factor the trinomial.. 16y2-6y-27 \n" ); document.write( "
Algebra.Com's Answer #38706 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
factor the trinomial..  16y²-6y-27 \r\n" );
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document.write( "Start out with this:\r\n" );
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document.write( "( y    )( y    )\r\n" );
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document.write( "There aren't too many pairs of positive\r\n" );
document.write( "integers which have product 27, so let's\r\n" );
document.write( "try 9 and 3 for the LASTS\r\n" );
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document.write( "( y   9)( y   3)\r\n" );
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document.write( "Now we have to think of a pair of factor\r\n" );
document.write( "pairs that have product 16.  Try 4 and 4\r\n" );
document.write( "for the FIRSTS:\r\n" );
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document.write( "(4y   9)(4y   3)\r\n" );
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document.write( "No that won't do, because the OUTER\r\n" );
document.write( "product would be 12y and the INNER\r\n" );
document.write( "product would be 36y and they don't\r\n" );
document.write( "differ by the middle term 6y.\r\n" );
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document.write( "So let's try 2 and 8 for the FIRSTS:\r\n" );
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document.write( "(2y   9)(8y   3)\r\n" );
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document.write( "No that won't do either, because the\r\n" );
document.write( "OUTER product would be 6y and the INNER\r\n" );
document.write( "product would be 72y and they don't\r\n" );
document.write( "differ by the middle term 6y.\r\n" );
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document.write( "So let's reverse the 2 and the 8:\r\n" );
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document.write( "(8y   9)(2y   3)\r\n" );
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document.write( "Now the OUTER product is 24y and the\r\n" );
document.write( "INNER product is 18y and 24y and \r\n" );
document.write( "whoopee! they DO differ by the middle\r\n" );
document.write( "term 6y.  Since the middle term is\r\n" );
document.write( "-6x we must make the 24y negative\r\n" );
document.write( "and the 18y positive, so we have:\r\n" );
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document.write( "(8y + 9)(2y - 3)\r\n" );
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document.write( "for the correct factorization.\r\n" );
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document.write( "Edwin
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