document.write( "Question 615265: A lab technician has one solution that is 80 percent chlorinated, and another that is 40 percent chlorinated. How much of each solution is needed to make a 100 Liter solution that is 50 percent chlorinated? \n" ); document.write( "

Algebra.Com's Answer #387041 by Alan3354(69443) $\"\"$ $\"About$

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A lab technician has one solution that is 80 percent chlorinated, and another that is 40 percent chlorinated. How much of each solution is needed to make a 100 Liter solution that is 50 percent chlorinated?
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\n" ); document.write( "Do it like this one:
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\n" ); document.write( "\n" ); document.write( "if a 14% acid solution is mixed with a 19% acid solution to produce 45 gallons of a 15% acid solution how much (in gallons) of each solution should be used?
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\n" ); document.write( "f = 14%
\n" ); document.write( "n = 19%
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\n" ); document.write( "f + n = 45 (total gallons)
\n" ); document.write( "14f + 19n = 15*45 (total acid)
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\n" ); document.write( "n = 45 - f
\n" ); document.write( "Sub for n
\n" ); document.write( "14f + 19*(45-f) = 675
\n" ); document.write( "14f + 855 - 19f = 675
\n" ); document.write( "-5f = -180
\n" ); document.write( "f = 36 gallons of 14%
\n" ); document.write( "n = 9 gallons of 19% \n" ); document.write( "

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