document.write( "Question 615209: What is the area of a square with the vertices (3,3),(6,6),(9,3)and (6,0)
\n" ); document.write( "A 3 square root of 2 units
\n" ); document.write( "B 12 square root of 2 units^2
\n" ); document.write( "C 18 units^2
\n" ); document.write( "D 36 units^2
\n" ); document.write( "this problem has been giving me the biggest headache if you would be so kind to send me the steps of how you solved it i would be very grateful \n" ); document.write( "
Algebra.Com's Answer #387011 by Alan3354(69443)\"\" \"About 
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What is the area of a square with the vertices (3,3),(6,6),(9,3)and (6,0)
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\n" ); document.write( "Call the vertices A, B, C & D
\n" ); document.write( "Arrange them:
\n" ); document.write( "A B C D A
\n" ); document.write( "3 6 9 6 3
\n" ); document.write( "3 6 3 0 3
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\n" ); document.write( "Add the diagonal products starting with the upper left
\n" ); document.write( "= 3*6 + 6*3 + 9*0 + 6*3 = 54
\n" ); document.write( "Add the diagonal products starting with the lower left
\n" ); document.write( "3*6 + 6*9 + 3*6 + 0*3 = 90
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\n" ); document.write( "The area = 1/2 the absolute value of the difference
\n" ); document.write( "= (1/2)*36
\n" ); document.write( "Area = 18
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\n" ); document.write( "This works for all polygons, any # of sides.
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