document.write( "Question 56813: 2x^2 + 3x=1 \n" ); document.write( "

Algebra.Com's Answer #38693 by checkley71(8403) $\"\"$ $\"About$

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2X^2+3X=1
\n" ); document.write( "2X^2+3X-1
\n" ); document.write( "using the quadratic equation we get
\n" ); document.write( "x=(-b+-sqrtb^2-4ac)/2a
\n" ); document.write( "x=(-3+-sqrt-3^2-4*2*-1)/2*2
\n" ); document.write( "x=(-3+-sqrt9+8)/4
\n" ); document.write( "x=(-3+-sqrt17)/4
\n" ); document.write( "x=(-3+4.123)/4
\n" ); document.write( "x=1.123/4
\n" ); document.write( "and
\n" ); document.write( "x=(-3-4.123)/4
\n" ); document.write( "x=-7.123/4
\n" ); document.write( " \n" ); document.write( "

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