document.write( "Question 615005: 15 houses line Indian Creek. The average space between each house exceeds the average width of each house by 80 feet. The sidewalk, 2920 feet in length, begins at a point 30 feet before the first house and ends at a point 30 feet beyond the last house. What is the average width, in feet, of each house? \n" ); document.write( "
Algebra.Com's Answer #386920 by ankor@dixie-net.com(22740)\"\" \"About 
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15 houses line Indian Creek.
\n" ); document.write( " The average space between each house exceeds the average width of each house by 80 feet.
\n" ); document.write( "The sidewalk, 2920 feet in length, begins at a point 30 feet before the first house and ends at a point 30 feet beyond the last house.
\n" ); document.write( " What is the average width, in feet, of each house?
\n" ); document.write( ":
\n" ); document.write( "Let w = the av width of the houses
\n" ); document.write( ":
\n" ); document.write( "Subtract the 30 ft from either side of the block of houses
\n" ); document.write( "2920 - 60 = 2860
\n" ); document.write( ":
\n" ); document.write( "Total width of the houses = 15w
\n" ); document.write( "Total spaces between houses = 14(w+80)
\n" ); document.write( ":
\n" ); document.write( "15w + 14(w+80) = 2860
\n" ); document.write( "15w + 14w + 1120 = 2860
\n" ); document.write( "29w = 2860 - 1120
\n" ); document.write( "29w = 1740
\n" ); document.write( "w = 1740/29
\n" ); document.write( "w = 60 ft the av width of each house \n" ); document.write( "
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