document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=614995>Question 614995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find two numbers such that the sum of twice the first and thrice the second is 92 and four times the first exceeds 7 times the second by 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386902 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find two numbers<BR>\n" );
document.write( "a & b<BR>\n" );
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document.write( "such that the sum of twice the first and thrice the second is 92<BR>\n" );
document.write( "2a + 3b = 92<BR>\n" );
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document.write( "and four times the first exceeds 7 times the second by 2<BR>\n" );
document.write( "4a = 7b + 2<BR>\n" );
document.write( "4a - 7b = 2<BR>\n" );
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document.write( "Multiply the 1st equation by 2, subtract from the above equation<BR>\n" );
document.write( "4a - 7b = 2<BR>\n" );
document.write( "4a + 6b = 184<BR>\n" );
document.write( "---------------subtraction eliminates a, find b<BR>\n" );
document.write( "0 - 13b = -182<BR>\n" );
document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-182%29%2F%28-13%29 ALIGN=MIDDLE  ALT=\"%28-182%29%2F%28-13%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b = +14 is the 2nd number<BR>\n" );
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document.write( "Find the 1st number using the 1st original equation<BR>\n" );
document.write( "2a + 3(14) = 92<BR>\n" );
document.write( "2a + 42 = 92<BR>\n" );
document.write( "2a = 92 - 42<BR>\n" );
document.write( "2a = 50<BR>\n" );
document.write( "a = 50/2<BR>\n" );
document.write( "a = 25 is the 1st number<BR>\n" );
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document.write( "Check solutions in the 2nd original equation<BR>\n" );
document.write( "4(25) = 7(14) + 2<BR>\n" );
document.write( "100 = 98 + 2; confirms our solutions of a=25 and b=14 </SPAN>\n" );
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