document.write( "Question 615027: Write an equation for the line that is perpendicular to the given line and that passes through a given point.\r
\n" ); document.write( "\n" ); document.write( "y=2/3x+9; (-6, 5)
\n" ); document.write( "Here is what I did:
\n" ); document.write( "negative reciprocal is -3/2)
\n" ); document.write( "y=mx+b
\n" ); document.write( "5=(3/2)*-6+b
\n" ); document.write( "then I get confused. Please help.Thank you very much.
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Algebra.Com's Answer #386868 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
y=2/3x+9; (-6, 5)
\n" ); document.write( "Here is what I did:
\n" ); document.write( "negative reciprocal is -3/2)
\n" ); document.write( "y=mx+b
\n" ); document.write( "5=(-3/2)*-6+b (you forgot the negative sign for the slope)
\n" ); document.write( "5=(18/2)+b
\n" ); document.write( "5=(9)+b
\n" ); document.write( "-5=b
\n" ); document.write( "So, your final equation is:
\n" ); document.write( "y=(-3/2)x+(-5)
\n" ); document.write( "or
\n" ); document.write( "y=-3/2x-5
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