document.write( "Question 614863: the sequence is defined recursively. Write the first five terms.
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document.write( "a1=2, a2=5; an=an-2 - 3an-1. \n" );
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Algebra.Com's Answer #386862 by ashipm01(26)![]() ![]() ![]() You can put this solution on YOUR website! The first two terms, a[1] and a[2], are the base cases. The following terms of the sequence are defined in terms of previous terms of the sequence (recursive sequence).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the first two terms are given in the problem statement: \n" ); document.write( "a[1] = 2 \n" ); document.write( "a[2] = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The next term, a[3], is given by a[3-2] - 3 * a[3-1]. \n" ); document.write( "a[3] = a[3-2] - 3 * a[3-1] \n" ); document.write( "= a[1] - 3 * a[2] \n" ); document.write( "= 2 - (3*5) \n" ); document.write( "= -13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then a[4] is given in terms of a[4-2] and q[4-1]: \n" ); document.write( "a[4] = a[4-2] - 3 * a[4-1] \n" ); document.write( "= a[2] - 3 * a[3] \n" ); document.write( "= 5 - (3 * -13) \n" ); document.write( "= 44\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Likewise, a[5] is given in terms of a[5-2] and a[5-1]: \n" ); document.write( "a[5] = a[5-2] - 3 * a[5-1] \n" ); document.write( "= a[3] - 3 * a[4] \n" ); document.write( "= -13 - (3 * 44) \n" ); document.write( "= -145\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the first five terms in the sequence are: {2, 5, -13, 44, -145} \n" ); document.write( " |