document.write( "Question 615000: sarah invested $1200 in the bank part at 9% per annum and the remainder at 4% per annum. after one year the 9% investment had $56 more interest. how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #386861 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! sarah invested $1200 in the bank part at 9% per annum and the remainder at 4% per annum. after one year the 9% investment had $56 more interest. how much was invested at each rate? \n" ); document.write( "------- \n" ); document.write( "0.09x - 0.04(1200-x) = 56 \n" ); document.write( "9x - 4*1200 +4x = 5600 \n" ); document.write( "13x = 5600+4800 \n" ); document.write( "13x = 10400 \n" ); document.write( "x = $800 (amt. invested at 9%) \n" ); document.write( "--- \n" ); document.write( "1200 -x = 400 (amt. invested at 4%) \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |