document.write( "Question 615000: sarah invested $1200 in the bank part at 9% per annum and the remainder at 4% per annum. after one year the 9% investment had $56 more interest. how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #386861 by stanbon(75887)\"\" \"About 
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sarah invested $1200 in the bank part at 9% per annum and the remainder at 4% per annum. after one year the 9% investment had $56 more interest. how much was invested at each rate?
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\n" ); document.write( "0.09x - 0.04(1200-x) = 56
\n" ); document.write( "9x - 4*1200 +4x = 5600
\n" ); document.write( "13x = 5600+4800
\n" ); document.write( "13x = 10400
\n" ); document.write( "x = $800 (amt. invested at 9%)
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\n" ); document.write( "1200 -x = 400 (amt. invested at 4%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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