document.write( "Question 614985: a)evaluate 2 power log5 base 3 - 5 power log2 base 3
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document.write( "b)(1/sqrt(27)^2-[log13 base5 - 2*log9 base 5] \n" );
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Algebra.Com's Answer #386851 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a)evaluate 2 power log5 base 3 - 5 power log2 base 3 \n" ); document.write( "Question: What do you mean by 2 power log5 base 3? \n" ); document.write( "------------------------------------------------------------ \n" ); document.write( "b)(1/sqrt(27)^2-[log13 base5 - 2*log9 base 5] \n" ); document.write( "--- \n" ); document.write( "= (1/27) -log5(13) - 2log5(9) \n" ); document.write( "---- \n" ); document.write( "= (1/27) - [log5(13)+log5(81)] \n" ); document.write( "--- \n" ); document.write( "= 1/27 -[log5[13*81] \n" ); document.write( "--- \n" ); document.write( "= 1/27 - log[1053)/log(5) \n" ); document.write( "--- \n" ); document.write( "= 1/27 - 4.3241.. \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " \n" ); document.write( " |