document.write( "Question 614861: A woman has part of $4500 invested at 4% and the rest at 6%. If her annual return on each investment is the same, then what is the average rate of interest, which she realizes on the $4500? \n" ); document.write( "
Algebra.Com's Answer #386826 by atul(1)\"\" \"About 
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Let A be invested at 4% and (4500 - A) at 6%\r
\n" ); document.write( "\n" ); document.write( "Interest at 4% is 0.04 * A\r
\n" ); document.write( "\n" ); document.write( "Interest at 6% is 0.06 (4500 - A)\r
\n" ); document.write( "\n" ); document.write( "Both are equal \r
\n" ); document.write( "\n" ); document.write( "0.04A = 0.06 * (4500 - A)\r
\n" ); document.write( "\n" ); document.write( "0.04A = 270 - 0.06 * A\r
\n" ); document.write( "\n" ); document.write( "0.1A = 270\r
\n" ); document.write( "\n" ); document.write( "A = 2700 and other investment is 4500-2700 = 1800
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