document.write( "Question 614930:
\n" ); document.write( "Given P(A), find P(not A).\r
\n" ); document.write( "\n" ); document.write( "P(A)=98%
\n" ); document.write( "

Algebra.Com's Answer #386790 by ashipm01(26)\"\" \"About 
You can put this solution on YOUR website!
If there is a 98% chance of event A happening, then there is a (100% - 98% = 2%) chance of event A not happening.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This is because: P(not A) = 1 - P(A)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So this means that either the even will happen, P(A), or the even will not happen, P(not A).
\n" ); document.write( "
\n" );