document.write( "Question 614930:
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document.write( "Given P(A), find P(not A).\r
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document.write( "P(A)=98% \n" );
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Algebra.Com's Answer #386790 by ashipm01(26)![]() ![]() ![]() You can put this solution on YOUR website! If there is a 98% chance of event A happening, then there is a (100% - 98% = 2%) chance of event A not happening.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is because: P(not A) = 1 - P(A)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So this means that either the even will happen, P(A), or the even will not happen, P(not A). \n" ); document.write( " |