document.write( "Question 614897: Can you help me with this problem? I can't remember of its completing the square or synthetic division or something else... I have a lot of others to do so could you walk me through this one so I can try to figure out the rest? Thanks!
\n" ); document.write( "6x^4+7x^3-37x^2-8x+12=0 solve for x.
\n" ); document.write( "Thank you so much!!
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Algebra.Com's Answer #386753 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
6x^4+7x^3-37x^2-8x+12=0 solve for x.
\n" ); document.write( "using rational roots theorem to solve:\r
\n" ); document.write( "\n" ); document.write( "...0...|.....6.....7.....-37......-8......12
\n" ); document.write( "...1...|.....6....13....-24......-32..-20(There is a root between 0 and 1)(change of sign)
\n" ); document.write( "...2...|.....6....19......1........-6......0 (2 is a root)
\n" ); document.write( "...3...|.....6....25.....38.....106...330 (3 is upper boundary)(numbers all positive)
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\n" ); document.write( "...0...|.....6....19......1.......-6
\n" ); document.write( ".-1...|.....6....13...-13........7(There is a root between 0 and -1)(change of sign)
\n" ); document.write( ".-2...|.....6....7.....-13......20
\n" ); document.write( ".-3...|.....6....1......-2.......0 (-3 is a root)
\n" ); document.write( ".-4...|.....6....-5......21.....-90 (4 is lower boundary)(numbers alternate in sign)
\n" ); document.write( "(x-2)(x+3)(6x^2+x-2)=0
\n" ); document.write( "(x-2)(x+3)(2x-1)(3x+2)=0
\n" ); document.write( "x=-3,-2/3,1/2,2
\n" ); document.write( "..
\n" ); document.write( "note: you can check your answers with a graphing calculator\r
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