document.write( "Question 614659: joses gas tank is 1/9 full after he buys 6 gallons it is 1/3 full how many can joses tank hold \n" ); document.write( "
Algebra.Com's Answer #386646 by Theo(13342) You can put this solution on YOUR website! x is the amount of gas that the tank can hold. \n" ); document.write( "when he starts he has 1/9 * x gallons of gas in the tank. \n" ); document.write( "after he buys 6 gallons he has 1/3 * x gallons of gas in the tank. \n" ); document.write( "your equation is: \n" ); document.write( "1/9 * x + 6 = 1/3 * x \n" ); document.write( "subtract 1/9 * x from both sides of this equation to get: \n" ); document.write( "6 = 1/3 * x - 1/9 * x \n" ); document.write( "since 1/3 is the same as 3/9, your equation becomes: \n" ); document.write( "6 = 3/9 * x - 1/9 * x \n" ); document.write( "simplify this by performing the subtraction to get: \n" ); document.write( "6 = 2/9 * x \n" ); document.write( "multiply both sides of this equation by (9/2) to get: \n" ); document.write( "9/2 * 6 = 9/2 * 2/9 * x \n" ); document.write( "this becomes: \n" ); document.write( "9/2 * 6 = x \n" ); document.write( "perform the indicated operations to get: \n" ); document.write( "54/2 = x which results in: \n" ); document.write( "x = 27 \n" ); document.write( "the tank holds 27 gallons. \n" ); document.write( "1/9 * 27 is equal to 3 gallons. \n" ); document.write( "that's what was in the tank when you started. \n" ); document.write( "add 6 gallons to this to get 9 gallons. \n" ); document.write( "you have 9 gallons after you added the 6 gallons. \n" ); document.write( "since the full tank is 27 gallons, the ratio of gas in the tank is now 9/27 which is the same as 1/3.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |