document.write( "Question 614579: what is the general form of the equation of a circle below
\n" ); document.write( "(x-4)^2+y^2=16\r
\n" ); document.write( "\n" ); document.write( "1)x^2+y^2-8x-16=16
\n" ); document.write( "2)x^2+y^2-8x+16=16
\n" ); document.write( "3)x^2+y^2-8x=0
\n" ); document.write( "4)x^2+y^2+8x=0 \n" ); document.write( "

Algebra.Com's Answer #386627 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "what is the general form of the equation of a circle below
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document.write( " (x-4)^2+y^2=16 
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document.write( "1)x^2+y^2-8x-16=16
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document.write( " 2)x^2+y^2-8x+16=16
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document.write( " 3)x^2+y^2-8x=0    || (x-4)^2 - 16 + y^2 = 0  or (x-4)^2 + y^2 = 16
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document.write( " 4)x^2+y^2+8x=0 \n" );
document.write( "

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