document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=614581>Question 614581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the verticies of the hyperboloa defined by this equation:\r<BR>\n" );
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document.write( "(x-2)^2 over 36 minus (y-2)^2 over 4 equals 1. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386625 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the verticies of the hyperboloa defined by this equation: <BR>\n" );
document.write( "(x-2)^2 over 36 minus (y-2)^2 over 4 equals 1<BR>\n" );
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document.write( "(x-2)^2/36-(y-2)^2/4=1<BR>\n" );
document.write( "This is an equation of a hyperbola with horizontal transverse axis.<BR>\n" );
document.write( "Its standard form: (x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center<BR>\n" );
document.write( "For given equation: (x-2)^2/36-(y-2)^2/4=1<BR>\n" );
document.write( "center: (2,2)<BR>\n" );
document.write( "a^2=36<BR>\n" );
document.write( "a=&#8730;36=6<BR>\n" );
document.write( "vertices: (2±a,2)=(2±6,2)=(-4,2) and (8,2) </SPAN>\n" );
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