document.write( "Question 614379: Two numbers are such that the ratio between them ir 3:5.if each is increased by 10,the ratio between the new numbers so formed is 5:7.find the original numbers. \n" ); document.write( "
Algebra.Com's Answer #386589 by ankor@dixie-net.com(22740)\"\" \"About 
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Two numbers are such that the ratio between them is 3:5.
\n" ); document.write( "If each is increased by 10, the ratio between the new numbers so formed is 5:7.
\n" ); document.write( "find the original numbers.
\n" ); document.write( ":
\n" ); document.write( "Let x = the multiplier
\n" ); document.write( "then
\n" ); document.write( "3x = one number
\n" ); document.write( "5x = the other number
\n" ); document.write( ":
\n" ); document.write( "\"If each is increased by 10, the ratio between the new numbers so formed is 5:7.\"
\n" ); document.write( "\"%28%283x%2B10%29%29%2F%28%285x%2B10%29%29\" = \"5%2F7\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "5(5x+10) = 7(3x+10)
\n" ); document.write( ":
\n" ); document.write( "25x + 50 = 21x + 70
\n" ); document.write( "25x - 21x = 70 - 50
\n" ); document.write( "4x = 20
\n" ); document.write( "x = 20/4
\n" ); document.write( "x = 5 is the multiplier
\n" ); document.write( "then
\n" ); document.write( "3(5) = 15 is the 1st number
\n" ); document.write( "5(5) = 25 is the 2nd number
\n" ); document.write( "
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