document.write( "Question 614379: Two numbers are such that the ratio between them ir 3:5.if each is increased by 10,the ratio between the new numbers so formed is 5:7.find the original numbers. \n" ); document.write( "
Algebra.Com's Answer #386589 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two numbers are such that the ratio between them is 3:5. \n" ); document.write( "If each is increased by 10, the ratio between the new numbers so formed is 5:7. \n" ); document.write( "find the original numbers. \n" ); document.write( ": \n" ); document.write( "Let x = the multiplier \n" ); document.write( "then \n" ); document.write( "3x = one number \n" ); document.write( "5x = the other number \n" ); document.write( ": \n" ); document.write( "\"If each is increased by 10, the ratio between the new numbers so formed is 5:7.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "5(5x+10) = 7(3x+10) \n" ); document.write( ": \n" ); document.write( "25x + 50 = 21x + 70 \n" ); document.write( "25x - 21x = 70 - 50 \n" ); document.write( "4x = 20 \n" ); document.write( "x = 20/4 \n" ); document.write( "x = 5 is the multiplier \n" ); document.write( "then \n" ); document.write( "3(5) = 15 is the 1st number \n" ); document.write( "5(5) = 25 is the 2nd number \n" ); document.write( " |